 Solution

Here $n=2$, $r_2=1$, and $d_K=-47$, so the Minkowski bound for ideal classes isEvery ideal class therefore has a representative of norm at most four. Such classes are generated by the prime ideals above $2$ and $3$. Putin additive notation. Since conjugate prime ideals represent inverse classes, the two principal-ideal factorizations from part (b) giveThus $y=-2x$ and $5x=0$, so the class group is generated by $x$ and has order dividing five.

It is not trivial. If ${\mathfrak{p}}_2$ were principal, there would be an element of norm two, butcannot equal two for integers $a,b$. Therefore $x\ne 0$. Since five is prime,