 Solution

Let $P(x)={\prod }_{i=1}^r(x-{\lambda }_i)$. Since both $x$ and $y$ are invertible on $X$, the formuladefines a regular map $F:X\to {\mathbb{A}}^1$.

Fix $t\in k$. To solve $F(x,y)=t$, setThe curve equation becomesThis is a nonconstant polynomial, so it has a root because $k$ is algebraically closed. At a root, neither $x$ nor $t-x$ can vanish, and the equation also forces $P(x)\ne 0$. The displayed value of $y$ is therefore defined and nonzero, satisfies $y^2=P(x)$, and obeys $F(x,y)=t$. Thus $F$ is surjective.