 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ii/paper-2/25h/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

τ = 0

everywhere, the third of the Frenet-Serret formulas gives

B^{'} = 0

, so

B

is a constant vector. Moreover

\frac{d}{d s} (α \cdot B) = T \cdot B = 0.

Thus $α (s) \cdot B$ is constant, and the image of $α$ lies in the plane perpendicular to $B$ .

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