 Solution

Let $H=V(L)$ for a nonzero homogeneous linear polynomial $L$. Because $H$ does not contain $X$, the restriction $L{|}_X$ is a nonzero section of ${\mathcal{O}}_X(1)$. Its zero divisor is the hyperplane-section divisor of a projective plane curvewhere $I_p(X,H)$ is the local intersection multiplicity; equivalently, it is the order of vanishing of $L{|}_X$ at $p$.

The curves $X$ and $H$ have no common component and have degrees $d$ and $1$. The Bézout theorem therefore gives