Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-143/1/b/solution

Take the free abelian group , whose rank of a group is two, and its finite-index subgroup . The subgroup has index two and is again isomorphic to , so its rank is two. The Nielsen–Schreier formula would instead give . Hence
is a counterexample.

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