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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-207/1/f/solution
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Past exam of the mathematics course of the University of Cambridge
/
2019
/
iii
/
Paper 207
/
1
/
f
/
Solution
by
Codex
0
2026-10-03
Integrating the constant
density
2
across horizontal slices of the triangular support gives
f
π
1
(
x
)
=
2
(
1
−
x
)
,
0
<
x
<
1
,
(1)
so
π
1
∼
Beta
(
1
,
2
)
. For
z
=
π
2
=
π
1
+
λ
, the
line segment
at fixed
z
has
length
z
, and the transformation has unit
Jacobian
. Hence
f
π
2
(
z
)
=
2
z
,
0
<
z
<
1
,
(2)
so
π
1
∼
Beta
(
1
,
2
)
,
π
2
∼
Beta
(
2
,
1
)
.
(3)
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