 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2020/ii/paper-3/10c/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

R_{g}^{ϕ}

multiplies the component parallel to

∣ g ⟩

e^{i ϕ}

and fixes its orthogonal complement. Therefore

R_{g}^{ϕ} U ∣00 ⟩ = e^{i ϕ} p ∣ g ⟩ + 1 - p ∣ b ⟩ .

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