 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2020/ii/paper-4/6b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

λ_{n} = λn

n

from

n - 1

and leaves it for

n + 1

\frac{d P _{1}}{d t} = - λ P_{1}, \frac{d P _{n}}{d t} = λ (n - 1) P_{n - 1} - λn P_{n} (n \geq 2) .

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