 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ib/paper-2/18h/b/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Normalizing the invariant distribution found in part (i) gives

1 = π_{0} (1 + \frac{q ^{2} p}{q - 1}), π_{1} = \frac{qp ( q - 1 )}{q - 1 + q ^{2} p} .

E_{1} T_{1}^{+} = \frac{1}{π _{1}} = \frac{q - 1 + q ^{2} p}{qp ( q - 1 )} .

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