 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ii/paper-3/7e/a/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The substitution

t \mapsto 1 - t

gives

B (p, q) = B (q, p)

. Direct integration gives

B (1, q) = \int_{0}^{1} (1 - t)^{q - 1} d t = \frac{1}{q} .

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