Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ii/paper-4/15d/d/solution
Past exam of the mathematics course of the University of Cambridge 2021 ii Paper 4 15D d Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
For a constant translation vector , take . Then and . The potential depends only on position differences and the kinetic energy only on momenta, so this is a symmetry and total momentum is conserved.
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