Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ii/paper-4/23h/b/solution

Because , is reflexive, so a bounded sequence has a weakly convergent subsequence . Then
and weak convergence handles . Thus the displayed limit holds (with the evident OCR correction on the right).
Strong convergence of the tests is essential: in take the same orthonormal sequence for and . Both converge weakly to zero, but .

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