 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ii/paper-4/28j/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

Put

c = (β + 1) / (β + 2)

e^{- θ}

δ (X) = c^{α + X}

c^{2 α} e^{θ (c^{2} - 1)} - 2 c^{α} e^{θ (c - 2)} + e^{- 2 θ} .

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