The <one-parameter subgroup> $\gamma_\xi(t)=\exp(t\xi)$ is the integral curve through the identity of $l_\xi$. Its defining initial-value problem is
$$
\dot\gamma_\xi(t)
=l_\xi(\gamma_\xi(t))
=(dL_{\gamma_\xi(t)})_e\xi,
\qquad
\gamma_\xi(0)=e.
$$

Solution

Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 115 / 4 / c / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-115/4/c/solution