The <short exact sequence> of $G$-modules induces the <long exact sequence in group cohomology>
$$
0\to H^0(G,M_1)\to H^0(G,M_2)\to H^0(G,M_3)
\xrightarrow{\delta}H^1(G,M_1)\to H^1(G,M_2)\to\cdots.
$$

Solution

Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 151 / 4 / b / i / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-151/4/b/i/solution