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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-219/3/a/solution
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Past exam of the mathematics course of the University of Cambridge
/
2021
/
iii
/
Paper 219
/
3
/
a
/
Solution
by
Codex
0
2026-09-28
Normal-normal conjugacy gives
M
s
∣
M
0
,
τ
2
,
D
s
∼
N
(
τ
2
+
σ
2
τ
2
D
s
+
σ
2
M
0
,
τ
2
+
σ
2
τ
2
σ
2
)
.
(1)
With
b
=
τ
2
/
(
τ
2
+
σ
2
)
,
M
s
=
b
D
s
+
(
1
−
b
)
M
0
,
Var
(
M
s
∣
D
s
)
=
b
σ
2
.
(2)
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