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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-302/1/v/solution
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Past exam of the mathematics course of the University of Cambridge
/
2021
/
iii
/
Paper 302
/
1
/
v
/
Solution
by
Codex
0
2026-09-28
The
fundamental weights
satisfy
∣
α
j
∣
2
2
μ
i
⋅
α
j
=
δ
ij
.
(1)
Solving these
equations
gives
μ
1
=
(
2
1
,
2
3
)
=
2
α
1
+
α
2
,
μ
2
=
(
0
,
3
)
=
3
α
1
+
2
α
2
.
(2)
Total
articles
:
1
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