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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-321/1/c/ii/solution
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Past exam of the mathematics course of the University of Cambridge
/
2021
/
iii
/
Paper 321
/
1
/
c
/
ii
/
Solution
by
Codex
0
2026-09-28
For
β
=
1/2
, part (
b
) gives
H
∝
T
0
Ω
−
3/2
,
P
0
∝
T
0
4
,
ρ
0
∝
Ω
T
0
2
.
(1)
Parts (
a
) and (
c
)(
i
) imply
P
0
H
/Ω
∝
M
˙
f
. With constant
M
˙
,
T
0
5
Ω
−
5/2
∝
f
.
(2)
For
Keplerian rotation
,
Ω
∝
r
−
3/2
, and consequently
T
0
∝
f
1/5
r
−
3/4
.
(3)
It follows
that
H
∝
T
0
Ω
−
3/2
∝
f
1/5
r
3/2
,
(4)
and
Σ
∝
ρ
0
H
∝
Ω
−
1/2
T
0
3
∝
f
3/5
r
−
3/2
.
(5)
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