Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-336/3/solution

The linear mode has frequency squared , so . To resolve the small frequency near threshold, write
The leading equation
and the initial data give
At , the equation for has a forcing whose component is
The Fredholm solvability condition removes this secular term and yields the slow amplitude equation
It has the conserved energy
The potential has maxima at
A periodic orbit launched from , exists only when that turning point lies inside the two maxima, namely
At equality the orbit is the separatrix; below it, the assumed real periodic oscillation is lost. Therefore

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