Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-336/3/solution
Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 336 3 Solution by
Codex 0 2026-09-29
The linear mode has frequency squared , so . To resolve the small frequency near threshold, writeThe leading equationand the initial data give
At , the equation for has a forcing whose component isThe Fredholm solvability condition removes this secular term and yields the slow amplitude equationIt has the conserved energyThe potential has maxima atA periodic orbit launched from , exists only when that turning point lies inside the two maxima, namelyAt equality the orbit is the separatrix; below it, the assumed real periodic oscillation is lost. Therefore
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