 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ia/paper-1/1b/a/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

∣ a - b ∣ = ∣ (a - z) + (z - b) ∣ \leq ∣ z - a ∣ + ∣ z - b ∣.

Hence the left-hand side of the proposed equation is always at least $∣ a - b ∣$ . There are no solutions when $c < ∣ a - b ∣$ .

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