 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ia/paper-1/5b/a/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

A \times (B \times C) = B (A \cdot C) - C (A \cdot B) .

Applying the same identity after reversing the outer cross product gives

(A \times B) \times C = B (A \cdot C) - A (B \cdot C) .

The formulas differ because the cross product is not associative.

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