 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ia/paper-2/11f/a/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The number of heads has the binomial distribution. Choosing the

k

head positions gives

P (exactly k heads) = (k n) p^{k} (1 - p)^{n - k} .

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