 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ia/paper-4/11c/b/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

K_{0} = \frac{1}{2} I ω^{2} .

The constant angular speed is

ω = 2 K_{0} / I

, so one full rotation takes

T = \frac{2 π}{ω} = 2 π \frac{I}{2 K _{0}} .

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