 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ib/paper-3/16c/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Using the polar-coordinate curl with

u_{θ} = r Ω (r)

gives

ω = \nabla \times u = (2Ω + r \frac{d Ω}{d r}) e_{z} .

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