 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ib/paper-4/15b/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Substitution of the stated phase into

i ℏ ψ_{t} = - \frac{ℏ ^{2}}{2 m} ψ_{xx} + m gx ψ

cancels the potential and scalar phase terms, leaving

i ℏ Φ_{t} = - \frac{ℏ ^{2}}{2 m} Φ_{xx} + i ℏ g t Φ_{x} .

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