 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ib/paper-4/5d/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

S = \frac{1}{μ _{0}} E \times B = \frac{ω}{μ _{0} k} (B_{1}^{2} + B_{2}^{2}) cos^{2} (k z - ω t) e_{z} .

It is the electromagnetic energy flux in the propagation direction; its time average is

c (B_{1}^{2} + B_{2}^{2}) / (2 μ_{0})

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