 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ii/paper-1/39c/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

p

independent of

r

. The axial Navier-Stokes equation reduces to

0 = - \frac{d p}{d z} + μ \frac{1}{r} \frac{d}{d r} (r \frac{d u}{d r}) + ρ g .

u (α R) = V, u (R) = 0 .

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