 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ii/paper-2/32e/a/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

This is not an asymptotic sequence, because

\frac{ψ _{n + 1} ( x )}{ψ _{n} ( x )} = (\frac{n + 1}{n})^{1/ x} ⟶ 1

x \to \infty

, rather than zero.

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