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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-101/6/b/solution
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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 101
/
6
/
b
/
Solution
by
Codex
0
2026-09-28
Localization of the inclusion
N
↪
M
gives an injection
S
−
1
N
↪
S
−
1
M
, whose
image
lies in
N
′
. Conversely, take
m
/
s
∈
N
′
. Since
s
/1
is
a
unit and
N
′
is an
S
−
1
A
-
submodule
,
1
m
=
1
s
s
m
∈
N
′
.
(1)
By the
definition
of the inverse
image
,
m
∈
N
, and hence
m
/
s
lies in the
image
of
S
−
1
N
. Therefore
N
′
≃
S
−
1
N
.
(2)
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