 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-160/3/c/ii/solution

i

h_{i} = λ_{i} + m - i .

Since

e ∣ m

r_{e} (i, λ_{i}) \equiv λ_{i} - i \equiv h_{i} - m \equiv h_{i} (mod e) .

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