 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-207/6/b/solution

Codex  0 Created 2026-09-28 Updated 2026-10-14

g (u, t) = \frac{P ( T > t ∣ U = u ) g ( u )}{S ( t )} = {1 + H_{0} (t)} e^{- u {1 + H_{0} (t)}}, u \geq 0.

1 + H_{0} (t)

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