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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-211/1/d/solution
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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 211
/
1
/
d
/
Solution
by
Codex
0
2026-09-28
Let
D
t
=
∑
s
=
1
t
N
s
δ
s
,
D
0
=
0
,
(1)
where the
sum
is componentwise, and
set
K
t
=
H
t
+
η
t
(
H
t
⋅
D
t
−
1
)
.
(2)
Then
X
t
x
,
K
=
H
t
⋅
(
δ
t
+
P
t
)
+
N
t
H
t
⋅
D
t
−
1
=
H
t
⋅
P
t
=
X
t
x
,
H
.
(3)
Also
K
t
+
1
⋅
P
t
=
H
t
+
1
⋅
P
t
, so subtracting the new holdings value gives
C
t
x
,
K
=
C
t
x
,
H
.
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