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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-211/4/c/solution
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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 211
/
4
/
c
/
Solution
by
Codex
0
2026-09-28
If
X
T
−
1
<
0
, then
X
T
≥
0
forces
H
T
=
0
and
a
strictly positive increment in the
H
T
direction. If
X
T
−
1
=
0
, that directional increment is strictly positive exactly when
X
T
>
0
. These disjoint cases give
P
(
ξ
>
0
)
=
P
(
X
T
>
0
,
X
T
−
1
=
0
)
+
P
(
X
T
−
1
<
0
)
.
(1)
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