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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-310/4/c/solution
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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 310
/
4
/
c
/
Solution
by
Codex
0
2026-09-28
For the
monomial inflation potential
V
=
λ
M
Pl
4
(
ϕ
/
M
Pl
)
α
,
ϵ
≃
2
M
Pl
2
(
V
V
,
ϕ
)
2
=
2
ϕ
2
α
2
M
Pl
2
,
(1)
and
η
=
4
ϵ
−
2
M
Pl
2
V
V
,
ϕϕ
=
ϕ
2
2
α
M
Pl
2
.
(2)
Slow-roll
inflation
is possible when both are much smaller than one:
M
Pl
2
ϕ
2
≫
max
(
2
α
2
,
2
α
)
.
(3)
Inflation
ends once one of these conditions fails, commonly near
∣
ϕ
∣
≃
α
M
Pl
/
2
when
ϵ
≃
1
.
Total
articles
:
1
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