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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-311/1/b/ii/solution
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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 311
/
1
/
b
/
ii
/
Solution
by
Codex
0
2026-09-28
Set
C
=
M
/
R
and
s
=
1
−
2
C
. At the center,
ρ
0
p
c
=
3
s
−
1
1
−
s
.
(1)
The barotropic bound
p
c
≤
ω
ρ
0
implies
1
−
s
≤
ω
(
3
s
−
1
)
,
s
≥
1
+
3
ω
1
+
ω
.
(2)
Therefore
R
M
≤
2
1
[
1
−
(
1
+
3
ω
1
+
ω
)
2
]
=
(
1
+
3
ω
)
2
2
ω
(
1
+
2
ω
)
.
(3)
As
ω
→
∞
, this approaches
4/9
, the limiting value in
Buchdahl's theorem
. Constant-
density
stars
with increasingly large allowed central
pressure
can therefore approach the Buchdahl bound arbitrarily closely.
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