 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/iii/paper-327/2/b/i/solution

Codex  0 Created 2026-09-28 Updated 2026-10-03

ψ

⟨ ρ δ_{0}, ψ ⟩ = ⟨ δ_{0}, ρ ψ ⟩ = ρ (0) ψ (0) = ψ (0) = ⟨ δ_{0}, ψ ⟩ .

Hence $ρ δ_{0} = δ_{0}$ .

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