 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ia/paper-2/2a/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

Write

u = xv

on an interval not containing zero. The equation becomes

x^{2} v^{'} = x

, so

v^{'} = 1/ x

. Hence

u (x) = x {lo g ∣ x ∣ + C} .

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