 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ia/paper-3/6d/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

A_{5}^{'}

is normal in

A_{5}

. It is nontrivial because

A_{5}

is nonabelian; simplicity of

A_{5}

therefore gives

A_{5}^{'} = A_{5} .

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