 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-1/16c/b/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

τ_{x y} (y) = μ u^{'} (y) = \frac{μU}{h} + G (y - \frac{h}{2}) .

The condition

τ_{x y} (0) = 0

therefore gives

G_{0} = \frac{2 μU}{h ^{2}} .

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