 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-1/18h/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

Independence gives

f_{μ} (x_{1}, x_{2}) = \frac{1}{2 π} exp [- \frac{1}{2} ((x_{1} - μ)^{2} + (x_{2} - μ)^{2})] .

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