 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-2/16d/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The temporal component found in part (a) gives directly

E (t) - E (0) = q \int_{0}^{t} E \cdot v (s) d s .

For a constant electric field, this is the work done by the field along the particle trajectory:

E (t) = E (0) + q E \cdot [x (t) - x (0)] .

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