 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-3/14a/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

g (k) = p^{'} (k) = ik p (k) .

Hence

p (k) = \frac{g ( k )}{ik}

for

k \neq = 0

. The assumed existence of the transforms excludes an arbitrary nonzero constant in

p

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