 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-3/14a/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

F^{- 1} [cos (ka)] (x) = \frac{1}{2} {δ (x + a) + δ (x - a)},

and

F^{- 1} [sin (ka)] (x) = \frac{1}{2 i} {δ (x + a) - δ (x - a)} .

δ

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