 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-4/15d/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

E < 0

and therefore

γ > 0

r \to \infty

, the terms proportional to

1/ r

are subleading and the Radial Schrodinger equation has dominant balance

R^{''} - γ^{2} R ≃ 0.

Its exponential behaviours are

e^{γ r}

and

e^{- γ r}

. The growing solution is not normalizable, so

R (r) \sim e^{- γ r} .

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