Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/iii/paper-133/3/a/solution

For each generator , let be its length in the generating set , and put
A shortest -word for has letters. Replacing each letter by an -word of length at most gives
Thus inclusion of any finitely generated subgroup is Lipschitz continuous for the corresponding word metrics.

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