Without administrative stopping, the probability that one patient experiences $A$ before $B$ is $\theta/(\theta+\phi)$. For $n$ patients the expected event count is therefore
$$
\mathbb E[v_+]=n\frac{\theta}{\theta+\phi}.
$$


Solution

Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 207 / 6 / b / i / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/iii/paper-207/6/b/i/solution