 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/iii/paper-224/2/b/solution

P_{n} (x_{1}^{n}) = P (Y_{1}^{n} = x_{1}^{n} ∣ Y_{1}^{n} \in B) = \frac{Q ^{n} ( x _{1}^{n} ) 1 _{{x_{1}^{n} \in B}}}{Q ^{n} ( B )} .

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