 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ia/paper-1/2c/a/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The

j

th column is

c_{j} = v + aj 1, v = (1 + b, 2 + b, 3 + b)^{T} .

All three columns therefore lie in the two-dimensional span of

v

and

1

, so

det A = 0 .

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