 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ia/paper-1/2c/a/iii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Every column lies in

span {v, 1}

. Conversely, differences of two columns are nonzero multiples of

1

, while any one column together with

1

recovers

v

. Hence

im A = span {(1 + b, 2 + b, 3 + b)^{T}, (1, 1, 1)^{T}},

and

rank A = 2 .

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