 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ia/paper-1/9f/iv/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

For the sequence in part (iii), part (ii) gives

(\frac{n !}{n ^{n}})^{1/ n} ⟶ e^{- 1} .

n \to \infty lim \frac{n}{( n ! ) ^{1/ n}} = e .

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